Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 252: 53

Answer

$S (t)= -16t^2 + V_0t + S $

Work Step by Step

$a(t)= -32ft/sec^2$ , $S(t)= -16t^2+V0t+S$ $V (t)= \int a(t) dt = \int(-32(t))dt = -32t + S$ $V(0)= -32 (0) + S$ $S=V (0) $ $V (t)= -32 + V(0) $ $\int(V (t))= \int(-32t+ V (0)) dt = (-32 (t^2/2))+ V(0)(t^1/1)+ S = -16t^2+V_0t+S$ $S (t)= -16t^2 + V_0t + S $
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