Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.1 Exercises - Page 252: 51

Answer

$h(t)= 0.75t^2+5t+12$ $h(6)=69 cm$

Work Step by Step

$\frac{dh}{dt}$=1.5t+5 dh=(1.5t+5t)dt h(t)=0.75$t^2$+5t+c h(0)=0+0+12 h(0)=12 h(6)=69 cm
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