Answer
$f(x)$ has two critical numbers : {$0, 2$}
Work Step by Step
$f'(x)=3x^2-6x=3x(x-2).$
$f'(x)=0\to 3x(x-2)=0\to x=0$ or $x=2.$
$f(x)$ has two critical numbers : {$0, 2$}.
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