Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.1 Exercises - Page 104: 64

Answer

$f(2)=2$ $f(2.1)=2.31525$ $f'(2)\approx 3.1525$

Work Step by Step

Evaluate $f(2)$ and $f(2.1)$. Then use the slope formula to estimate $f'(2)$: $f(2)=\frac{1}{4}2^3$ $f(2)=2$ $f(2.1)=\frac{1}{4}2.1^3$ $f(2.1)=2.31525$ $f'(2)\approx \frac{2-2.32515}{2-2.1}$ $f'(2)\approx 3.1525$
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