Answer
tanx - x +C
Work Step by Step
We find:
$\int$tan$^2$xdx
=$\int($sec$^2$x-1)dx
=$\int$sec$^2$xdx-$\int$1dx
$\int$sec$^2$xdx=tanx+$C_{1}$ and $\int$1dx=x+$C_{2}$
So the expression is tanx - x +C
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 4 - Integration - 4.2 The Indefinite Integral - Exercises Set 4.2 - Page 280: 69
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