Answer
\[
0=-3 y-4 z+2 x
\]
Work Step by Step
The equation of a plane passing through the point $(a, b, c)$ and having normal vector $\langle l, m, n\rangle$ is
\[
0=(-a+x)l+(-b+y)m+(-c+z)n
\]
The equation of the plane is
\[
\begin{array}{c}
0=(-0+x) \cdot2- (-0+y)\cdot3-(-0+z) \cdot4 \\
0=0=-3 y-4 z+2 x
\end{array}
\]
