Answer
\[
28=2 z+4 y+x
\]
Work Step by Step
The equation of a plane passing through the point $(a, b, c)$ and having normal vector $\langle l, m, n\rangle$ is
\[
0=(-a+x)l+(-b+y)m+(-c+z)n
\]
The equation of the plane is
\[
\begin{array}{c}
0=(-2+x) \cdot1+(-6+y) \cdot4+(-1+z) \cdot2 \\
0=-2+x-24+4 y-2 +2 z\\
28=x+4 y+2 z
\end{array}
\]
