Answer
\[
0=z
\]
Work Step by Step
The equation of a plane passing through the point $(a, b, c)$ and having normal vector $\langle l, m, n\rangle$ is
\[
0=(-a+x)l+(-b+y)m+(-c+z)n
\]
The equation of the plane is
\[
\begin{array}{c}
0=(-1+x) \cdot 0+ (-0+y)\cdot 0+(-0+z) \cdot1 \\
0=0+0+z
\end{array}
\]
