Answer
$g^{-1}(4)=0$
Work Step by Step
Let $g^{-1}(4)=a$
$g(a)=3+a+e^a=4$
$a+e^a=1$
try $a=0$
LHS=$0+e^0=1$=RHS
$\therefore g^{-1}(4)=0$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 64: 17
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