Answer
$f^{-1}(17)=6$
$f(2)=3$
Work Step by Step
$\because f(6)=17, f^{-1}(f(6))=f^{-1}(17), f^{-1}(17)=6$
$\because f^{-1}(3)=2, f(f^{-1}(3))=f(2), f(2)=3$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 64: 15
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