Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 64: 10

Answer

No

Work Step by Step

$f(2) = 0 = f(-2)$, hence there are two values from the domain that map to the same value in the range of $f(x)$, and it is not a one-to-one function. Alternatively, the function fails the Horizontal Line Test.
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