Answer
$g(t)=t^{2}$
$f(t)=\sec t\tan t$
Work Step by Step
Separating the function into two processes:
$1. g(t)=t^{2}$
$2. f(g(t))=f(t^{2})=\sec t^{2}\tan t^{2}=\sec g(t)\tan g(t)$
$f(t)=\sec t\tan t$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises - Page 44: 49
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