Answer
$g(x)=\frac{x}{1+x}$
$f(x)=\sqrt[3] x$
Work Step by Step
Separating the function into two processes:
$1. g(x)=\frac{x}{1+x}$
$2. f(g(x))=f(\frac{x}{1+x})=\sqrt[3] \frac{x}{1+x}=\sqrt[3] (g(x))$
$f(x)=\sqrt[3] x$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises - Page 44: 48
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