Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 9 - Section 9.4 - Applications Involving Pairs of Linear Equations - Exercises - Page 338: 8

Answer

The quantity of $40\%$ butterfat cream is $\frac{625}{19}\;lb$ and the quantity of $2\%$ butterfat milk is $\frac{1750}{19}\;lb$.

Work Step by Step

Let the quantity of $40\%$ butterfat cream is $x$ and the quantity of $2\%$ butterfat milk is $y$. Total quantity is $=125\;lb$. $\Rightarrow x+y=125$ ...... (1) $40\;\%$ of $x$ quantity plus $2\;\%$ of $y$ quantity equal to $12\;\%$ of $125\;lb$. $\Rightarrow 0.40x+0.02y=15$ ...... (2) Multiply equation (1) by $-0.02$. $\Rightarrow -0.02x-0.02y=-2.5$ ...... (3) Add equation (2) and (3). $\Rightarrow 0.40x+0.02y-0.02x-0.02y=15-2.5$ Simplify. $\Rightarrow 0.38x=12.5$ Divide both sides by $0.38$. $\Rightarrow x=\frac{12.5}{0.38}$ Simplify. $\Rightarrow x=\frac{625}{19}$ Substitute the value of $x$ into equation (1). $\Rightarrow \frac{625}{19}+y=125$ Subtract $\frac{625}{19}$ form both sides. $\Rightarrow y=125-\frac{625}{19}$ $\Rightarrow y=\frac{2375}{19}-\frac{625}{19}$ $\Rightarrow y=\frac{2375-625}{19}$ $\Rightarrow y=\frac{1750}{19}$ Hence, the quantity of $40\%$ butterfat cream is $\frac{625}{19}\;lb$ and the quantity of $2\%$ butterfat milk is $\frac{1750}{19}\;lb$.
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