Answer
$$0.13\ \Omega A.$$
Work Step by Step
We have
$$(4.7\ \Omega)(0.0281\ A)=0.13207\ \Omega A.$$
Now, round this product to two significant digits, which is the accuracy of the least accurate measurement $4.7\ \Omega$. That is,
$$(4.7\ \Omega)(0.0281\ A)=0.13\ \Omega A.$$