Answer
$$35\ A^2 \Omega$$
Work Step by Step
We have
$$
(0.480 \ A)^2(150 \ \Omega )=34.56\ A^2 \Omega
.$$
Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is,
$$34.56\ A^2 \Omega= 35\ A^2 \Omega$$
