Answer
$$48 \times 10^{-6}\ m^3.$$
Work Step by Step
We have
$$(0.045 \ m)(0.0292 \ m)(0.0365 \ m)= 0.000048 \ m^3.$$
Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is,
$$(0.045 \ m)(0.0292 \ m)(0.0365 \ m)= 48 \times 10^{-6}\ m^3.$$
