Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 37

Answer

$$8.97\times 10^{6}. $$

Work Step by Step

We have $$\sqrt{80.5\times 10^{12}}=(80.5\times 10^{12})^{1/2}\\ =8.97\times 10^{6}. $$
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