Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 25

Answer

$$14.9\times 10^{18}.$$

Work Step by Step

We have $$ (35.5\times 10^{6} ) (420\times 10^{9})=14910 \times 10^{15}\\ =14.9\times 10^{18}.$$
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