Answer
$$123 \times 10^{21}. $$
Work Step by Step
We have
$$(350\times 10^{9})^2=122500 \times 10^{18}=123 \times 10^{21}. $$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 2 - Section 2.7 - Engineering Notation - Exercises - Page 130: 35
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