Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.6 - Radian Measure - Exercise - Page 418: 28

Answer

$10.53 \; rad$.

Work Step by Step

The given values are Wheel diameter $d=6.00 \; m$. Distance travelled $s=31.6 \; m$. We know: $r=\frac{d}{2}$. Plug in the value of $d$. $ r= \frac{6.00}{2}\; m $ Simplify. $r= 3.00\; m$ The formula is $s=r\theta$. Isolate $\theta$. $\theta=\frac{s}{r}$ $\theta=\frac{31.6 \; m}{3.00\; m}$ Simplify. $\theta=10.53 \; rad$.
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