Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.6 - Radian Measure - Exercise - Page 418: 17

Answer

$33\pi~cm$

Work Step by Step

First, since $330^o= 330\times\frac{\pi}{180} \ rad=\frac{11\pi}{6} rad$, then using the relation $s=r\theta$, we have $$ s=r\theta=18\times \frac{11\pi}{6}=33\pi~cm .$$
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