Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.6 - Radian Measure - Exercise - Page 418: 15

Answer

$$\frac{3\pi}{2} .$$

Work Step by Step

Since $45^o= 45\times\frac{\pi}{180} \ rad= \frac{\pi}{4}\ rad$, then using the relation $s=r\theta$, we have $$ s=r\theta=6\times \frac{\pi}{4}=\frac{3\pi}{2} .$$
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