Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 401: 44

Answer

The area remaining in the triangle is $A=593~cm^{2}$

Work Step by Step

The remaining area of the triangle (let's call it $A$) is the total area of the equilateral triangle minus the area of the square hole. The formula to calculate the area of an equilateral triangle is $A=\frac{\sqrt 3a^{2}}{4}$. The formula to calculate the area of the square hole is $A=s^{2}$. Subtracting these two areas gives: $A=\frac{\sqrt 3a^{2}}{4}-s^{2}=\frac{\sqrt 3(40cm)^{2}}{4}-(10cm)^{2}=592.83cm^{2}\approx 593~cm^2$
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