Answer
$A=145~in^{2}$
Work Step by Step
Since the hole is a triangle, we use the triangle area formula:
$A=\frac{bh}{2}$
where the lengths are:
$b=26.4in$
$h=11in$
Thus, we have the area:
$A=\frac{(26.4in)(11.0in)}{2}=145.2in^{2}\approx145~in^2$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 12 - Section 12.3 - Triangles - Exercise - Page 401: 43
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
