Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 401: 41

Answer

the distance flown by the helicopter is $c =74.3~mi$

Work Step by Step

The distance the helicopter has flown (we can call it $c$) can be calculated as the hypotenuse of the right triangle using the Pythagorean Theorem. We have the sides: $a = 62 mi$ $b = 41 mi$ Thus, we have: $c^2=a^2+b^2$ $c=\sqrt{62^2+41^2}$ $c = \sqrt {(62 mi)^{2} + (41mi)^{2}} = 74.3~mi$
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