Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 399: 19

Answer

$a = 16.6$ $ inches$

Work Step by Step

The offset distance $x$ is simply one of the side of the pipe. We have the sides: $c = 18 in$ $b = 7 in$ and $a$ would be our offset distance $x$. We use the Pythagorean theorem to find $x$: $a^2+b^2=c^2$ $x=a=\sqrt{c^2-b^2}$ $x = \sqrt {(18in)^{2} - (7in)^{2}} = 16.6in$
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