Answer
Total depth of cut = $0.57$ inches
Work Step by Step
Using the formula given in the exercise, we have:
$total~depth =r-\sqrt {r^{2}-(\frac{l}{2})^{2}}$ + shaft depth
Where
$h$ = height of the segment
$r$ = radius of the shaft $= \frac{3.720in}{2}= 1.86~in$
$l$ = length of the chord $= 1.750~in$
So,
$total~depth =r-\sqrt {r^{2}-(\frac{l}{2})^{2}}$ + shaft depth
$total~depth = 1.86 in - \sqrt {(1.86in)^{2}-(\frac{1.750in}{2})^{2}} + 0.350 in=0.57~in$
Thus, the total depth of cut is $0.57 in$
