Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Mid-Chapter Check Point - Page 594: 8

Answer

$-4x^{10}\sqrt{2x}$

Work Step by Step

$-\sqrt{32x^{21}}$ Factor out perfect squares. $-\sqrt{(16)(2)x^{20}x}$ Simplify $-4x^{10}\sqrt{2x}$
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