Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Mid-Chapter Check Point - Page 594: 3

Answer

$4x\sqrt{6x}$

Work Step by Step

$\sqrt{96x^3}$ Factor out perfect squares. =$\sqrt{(16)(6)(x^2)(x)}$ Simplify. =$4x\sqrt{6x}$
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