Answer
$(y-3)(5y-1)$
Work Step by Step
Factoring by grouping:
1. Multiply the leading coefficient, a, and the constant, c.
2. Find the factors of ac whose sum is b.
3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2.
4. Factor by grouping
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Always start by searching for a GCF ... (there are none other than 1).
1. $\quad ac=+15$
2. $\quad$sum = $-16 \quad$... factors: $-15$ and $-1$
3. $\quad 5y^{2}-16y+3=(5y^{2}-15y)+(-y+3)$
4. $\quad$... $=5y(y-3)+(-1)(y-3) =(y-3)(5y-1)$
Check by FOIL$\qquad (y-3)(5y-1)$ =
$F:\quad 5y^{2}$
$O:\quad -y$
$I:\quad -15y$
$L:\quad +3$
$(y-3)(5y-1)$ = $5y^{2}-116y+3$
