Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 610: 98

Answer

Does not make sense. The equation can quickly be solved by applying the square root property. $25x^2-169=0$ Add $169$ to both sides: $25x^2-169+169=0+169$ $25x^2=169$ Divide both sides by $25$. Thus, the equation becomes: $x^2=\frac{169}{25}$ If $u^2 = d$, then $u = \sqrt d$ or $u = -\sqrt d$. Hence, $x=±\sqrt{\frac{169}{25}}$ $x=±\frac{13}{5}$

Work Step by Step

Does not make sense. The equation can quickly be solved by applying the square root property. $25x^2-169=0$ Add $169$ to both sides: $25x^2-169+169=0+169$ $25x^2=169$ Divide both sides by $25$. Thus, the equation becomes: $x^2=\frac{169}{25}$ If $u^2 = d$, then $u = \sqrt d$ or $u = -\sqrt d$. Hence, $x=±\sqrt{\frac{169}{25}}$ $x=±\frac{13}{5}$
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