Answer
$x=-2$ or $x=-4$
Work Step by Step
$x^2 + 6x + 8 = 0$
The equation is already in the form $ax^2 + bx + c = 0$.
$a=1$, $b=6$, $c=8$.
Plug these values in the quadratic formula: $x = \frac{-b±\sqrt{b^2-4ac}}{2a}$
$x = \frac{-6±\sqrt{6^2-(4⋅1⋅8)}}{2⋅1}$
$x = \frac{-6±\sqrt{36-32}}{2}$
$x = \frac{-6±\sqrt{4}}{2}$
$x = \frac{-6±2}{2}$
$x = \frac{-6+2}{2}$ or $x = \frac{-6-2}{2}$
$x=-2$ or $x=-4$
