Answer
$x = \frac{1}{2}$ or $x = -4$
Work Step by Step
$(2x + 3)(x + 2) = 10$
Simplify the equation.
$2x^2+5x+6=10$
Subtract $10$ to both sides.
$2x^2+7x+6-10=10-10$
$2x^2+7x-4=0$
Use the quadratic formula: $x = \frac{-b±\sqrt{b^2-4ac}}{2a}$
$a=2$, $b=7$, $c=-4$
$x = \frac{-7±\sqrt{7^2-(4⋅2⋅-4)}}{(2⋅2)}$
$x = \frac{-7±\sqrt{49-(-32)}}{4}$
$x = \frac{-7±\sqrt{81}}{4}$
$x = \frac{-7±9}{4}$
$x = \frac{2}{4}$ or $x = \frac{-16}{4}$
$x = \frac{1}{2}$ or $x = -4$
