Answer
$x=±\sqrt{13}i$
Work Step by Step
$2x^2 + 26 = 0$
Subtract $26$ to both sides.
$2x^2 + 26-26 = 0-26$
$2x^2 = -26$
Divide both sides $2$.
$\frac{2x^2}{2} = \frac{-26}{2}$
$x^2 = -13$
$x=±\sqrt{-13}$
$x=±\sqrt{13}i$
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