Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 552: 31

Answer

The graphs are not the same.

Work Step by Step

Given \begin{equation} \begin{aligned} & (\sqrt{x}-1)(\sqrt{x}-1)=x+1 \\ & {[0,5,1] \text { by }[-1,2,1]} \end{aligned} \end{equation} Let \begin{equation} \begin{aligned} f(x)&= (\sqrt{x}-1)(\sqrt{x}-1) \\ g(x)&=x+1 \\ \end{aligned} \end{equation} The graphs of both functions are shown in the figure and are clearly not the same. They will be the same if we choose: \begin{equation} \begin{aligned} g(x)&= (\sqrt{x}-1)^2\\ &=x-2\sqrt{x}+1 \\ \end{aligned} \end{equation}
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