Answer
$2x^2y^3 \sqrt{2xy}$.
Work Step by Step
The given expression is
$=\sqrt{8x^5y^7}$
Factor the radicands:
$=\sqrt{2^2\cdot 2x^4xy^6y}$
Group the perfect square factors.
$=\sqrt{2^2x^4y^6\cdot 2xy}$
Factor into two radicals.
$=\sqrt{2^2x^4y^6}\cdot \sqrt{2xy}$
Simplify.
$=2x^2y^3 \sqrt{2xy}$.
