Answer
$2x^{2}y^{4}\sqrt[4] {2x^3y}$.
Work Step by Step
The given expression is
$=\sqrt[4] {32x^{11}y^{17}}$
Factor the radicands as a power of $4$.
$=\sqrt[4] {2^4\cdot 2x^{8}x^3y^{16}y^1}$
Group the power of $4$ radicands.
$=\sqrt[4] {(2^4x^{8}y^{16})\cdot (2x^3y^1)}$
Factor into two radicals.
$=\sqrt[4] {(2^4x^{8}y^{16})}\cdot \sqrt[4] {(2x^3y^1)}$
Simplify.
$=2x^{2}y^{4}\sqrt[4] {2x^3y}$.
