Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Mid-Chapter Check Point - Page 541: 17

Answer

$14\sqrt[3] {2}$.

Work Step by Step

The given expression is $=4\sqrt[3] {16}+2\sqrt[3]{54}$ Factor the radicands using the greatest perfect cube factors. $=4\sqrt[3] {2^3\cdot 2}+2\sqrt[3]{3^3\cdot 2}$ Take the cube root of each factor. $=4\sqrt[3] {2^3}\cdot \sqrt[3] {2}+2\sqrt[3]{3^3}\cdot \sqrt[3] {2}$ Simplify. $=4\cdot 2\cdot \sqrt[3] {2}+2\cdot 3\cdot \sqrt[3] {2}$ Multiply. $=8\sqrt[3] {2}+6 \sqrt[3] {2}$ Apply the distributive property. $=(8+6)\sqrt[3] {2}$ Simplify. $=14\sqrt[3] {2}$.
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