Answer
Solution set = $\{15\}$.
Work Step by Step
First, we exclude those values of x that yield a zero in any of the denominators.
$x\not\in\{-3,3\}\qquad (*)$
Multiply the equation with the LCD=$(x-3)(x+3)$
$ 6(x-3)=4(x+3)\qquad$ ... simplify (distribute)
$ 6x-18=4x+12\qquad$ ... add $18-4x$
$6x-4x=12+18$
$2x=30$
$ x=15\qquad$ ...Checking (*), this is a valid solution
Solution set = $\{15\}$.
