Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.6 - Rational Equations - Exercise Set - Page 462: 21

Answer

$x=3$ or $x=-6$.

Work Step by Step

LCD$=3x$, thus multiplying both sides by the LCD: $3x(\frac{6}{x}-\frac{x}{3})=3x(1)\\x^2+3x-18=0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x+6)(x-3)=0$ Thus $x=3$ or $x=-6$.
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