Answer
Solution set = $\emptyset$.
(no solution)
Work Step by Step
First, we exclude those values of x that yield a zero in any of the denominators.
$x\not\in\{-3\}\qquad (*)$
Multiply the equation with the LCD=$(x+3)$
$ x+6=3+2(x+3)\qquad$ ... simplify (distribute)
$x+6=3+2x+6$
$ x+6=2x+9\qquad$ ... add $-6-2x$
$x-2x=9-6$
$-x=3$
$ x=3\qquad$ ...Checking (*), this is not a valid solution
Solution set = $\emptyset$.
(no solution)
