Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Mid-Chapter Check Point - Page 364: 4

Answer

$3x^3+4x^2-39x+40$

Work Step by Step

$(3x-5)(x^2+3x-8)=3x\cdot x^2+3x\cdot3x+3x\cdot(-8)-5\cdot x^2-5\cdot3x-5\cdot(-8)=3x^3+9x^2-24x-5x^2-15x+40=3x^3+4x^2-39x+40$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.