Answer
$-2x^7y^3z^5$
Work Step by Step
$(6x^2yz^4)(-\frac{1}{3}x^5y^2z)=\\=(6\cdot-\frac{1}{3})(x^2x^5)(yy^2)(z^4z)\\=-2x^7y^3z^5$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Mid-Chapter Check Point - Page 364: 2
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