Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Mid-Chapter Check Point - Page 364: 19

Answer

$(x-8)(x+3)$.

Work Step by Step

The given expression is $=x^2-5x-24$ Rewrite the middle term $-5x$ as $3x-8x$. $=x^2-8x+3x-24$ Group terms. $=(x^2-8x)+(3x-24)$ Factor each term-. $=x(x-8)+3(x-8)$ Factor out $(x-8)$. $=(x-8)(x+3)$.
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