Answer
$9x^4-6x^2y+y^2$
Work Step by Step
The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$.
Hence here: $(3x^2-y)^2=(3x^2)^2-2\cdot3x^2\cdot y+y^2=9x^4-6x^2y+y^2$
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