Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Cumulative Review Exercises - Page 402: 1

Answer

$4$

Work Step by Step

Given: $8(x+2)-3(2-x)=4(2x+6)-2$ $8x+16-6+3x=8x+24-2$ or,$8x+10+3x=8x+22$ This implies that $8x+10+3x-8x-22=0$ or, $3x+12=0$ Hence, $x=4$
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