Answer
$16y^2-56y+49$.
Work Step by Step
Use the special-product formula shown below.
$(A-B)^2=A^2-2AB+B^2$
Let $A=4y$ and $B=7$.
Substitute the values into the formula.
$\Rightarrow (4y-7)^2=(4y)^2-2(4y)(7)+(7)^2$
Clear the parentheses.
$\Rightarrow (4y-7)^2=16y^2-56y+49$.
