Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 208: 76

Answer

The equation is $ 16a+4b+c=1682 $.

Work Step by Step

The given equation is $ y=ax^2+bx+c $ ... (1). Substitute $ x=4 $ and $ y=1682 $ into the equation (1). $ 1682=a(4)^2+b(4)+c $ Clear parentheses. $ 1682 = 16a+4b+c $ Rearrange. $ 16a+4b+c=1682 $.
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