Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 208: 69

Answer

Actual score $=95$.

Work Step by Step

Let the actual test score is $10t+u$. Reversed test score is $10u+t$. The difference of both scores is equal to $36$. In the equation we can write. $\Rightarrow (10t+u)-(10u+t)=36$ Simplify. $\Rightarrow 10t+u-10u-t=36$ Add like terms. $\Rightarrow 9t-9u=36$ Apply distributive property. $\Rightarrow 9(t-u)=36$ Divide both sides by $9$. $\Rightarrow t-u=4$ ...... (1) The sum of the actual test scores is $14$. In the equation we can write. $\Rightarrow u+t=14$ ...... (2) Add equation (1) and (2). $\Rightarrow t-u+u+t=4+14$ Add like terms. $\Rightarrow 2t=18$ Divide both sides by $2$. $\Rightarrow t=9$ Substitute the value of $t$ into equation (2). $\Rightarrow u+9=14$ Subtract $9$ from both sides. $\Rightarrow u+9-9=14-9$ Simplify. $\Rightarrow u=5$ Actual score $=10t+u$. Plug both values. $=10(9)+5$ $=90+5$ $=95$.
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